Thread: ajax send problem
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05-23-2007, 11:24 PM
 #2
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You don't want to be sending anything within the send() call since this is a GET request. That would be alright if you were POSTing the data, but for a GET you just append the data to the URL ("time.php?name=...").

Code:
var url = "time.php?name=" 
        + document.myForm.username.value 
        + "&password=" 
        + document.myForm.password.value;
xmlHttp.open("GET", url, true);
xmlHttp.send(null);