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09-13-2008, 01:00 PM
#5
Etch! is offline Etch!
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look , deadlock occurs usually when one instruction's input is the result of another instruction ... which in turns waits for the first one's result .. like this:

1. a = func1( b , c);
2. b = func2( a , c);

here deadlock occurs , coz func1 waits for func2's result , and func2 waits for func1's result !

this situation happens in the operating system occasionally when a process is fetched from the waiting list of a processor , while another process is beying processed and already waiting for some other waiting process result !
like I/O operation ( Data Transaction / Network actions )